Answer: [tex]\dfrac{20}{7}[/tex]
Step-by-step explanation:
Given
The ratio of the area of the similar triangles is equal to the square of the side of the corresponding sides
Suppose the corresponding side on figure A is [tex]x[/tex]
On solving
[tex]\Rightarrow \dfrac{16}{49}=[\dfrac{x}{5}]^2\\\\\Rightarrow \dfrac{x}{5}=\sqrt{\dfrac{16}{49}}\\\\\Rightarrow \dfrac{x}{5}=\dfrac{4}{7}\\\\\Rightarrow x=\dfrac{20}{7}[/tex]
