nidashad46 nidashad46

29-04-2021
Mathematics

contestada

Given f(x) = 3x2 + kx + 19, and the remainder when
f(x) is divided by x + 3 is 37, then what is the value of k?

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fredagyau5 fredagyau5

29-04-2021

Answer:

[tex]f{x} = x + 3 = 0 \\ x = - 3 \\ f( - 3) = 3( - 3) {}^{2} + k( - 3) + 19 = 37 \\ f( - 3) = 27 - 3k + 19 = 37 \\ f( - 3) = 46 - 3k = 37 \\ f( - 3) = 46 - 37 = 3k \\ f( - 3) = 9 = 3k \\ f( - 3) = k = 3[/tex]

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