Answer:
[tex](x-3)^{2} = 10[/tex]
Step-by-step explanation:
[tex]\\Question 1\\\\-2xc = -6x\\2xc = 6x\\c = \frac{6}{2} \\c = 3\\x^{2} - 6x + cx^{2} = 1 + c^{2} \\x^{2} - 6x + 3^{2} = 1 + 3^{2}\\x^{2} - 6x + 9 = 1 + 9\\x^{2} - 6x + 9 = 10\\(x - 3)^{2} = 10\\REWRITINGx^{2} - 6x = 1 is equal (x -3)^{2} = 10\\[/tex]
I hope this help!
I don't know the second one ^-^
