Answer:
The correct solution is "1230 K".
Explanation:
The given values are:
[tex](V_{rms})_1= 200 \ m/sec[/tex]
[tex](V_{rms})_2= 350 \ m/sec[/tex]
[tex]T_1=400 \ K[/tex]
As we know,
⇒ [tex]V_{rms} \propto \sqrt{T}[/tex]
or,
⇒ [tex]\frac{(V_{rms})_1}{(V_{rms})_2} =\sqrt{\frac{T_1}{T_2} }[/tex]
On substituting the values, we get
⇒ [tex]\frac{200}{350} =\sqrt{\frac{400}{T_2} }[/tex]
⇒ [tex]T_2=1230 \ K[/tex]
