In ΔDEF, the measure of ∠F=90°, the measure of ∠D=70°, and EF = 4.4 feet. Find the length of FD to the nearest tenth of a foot.

Respuesta :

Answer:

FD= 1.6 ft

Step-by-step explanation:

Seems like an easy trig question so let's get to it.

1) Draw the right triangle to make it easier to solve (right triangle because we have a 90 degree angle)

2) Find the last angle measure by adding 90+70= 160 and 180-160= 20 so the last angle measure is 20.

3) Use trig function, tan20= x/4.4 to find the answer of x (FD) to be 1.6. Therefore, the FD value will be 1.6 ft.

Answer:

1.6

Step-by-step explanation:

( i submitted it and got it correct, this is the copy and pasted work it shows )

tanD=  

adjacent

opposite

​  

=  

x

4.4

​  

 

\tan 70=\frac{4.4}{x}

tan70=  

x

4.4

​  

 

x\tan 70=4.4

xtan70=4.4

Cross multiply.

\frac{x\tan 70}{\tan 70}=\frac{4.4}{\tan 70}

tan70

xtan70

​  

=  

tan70

4.4

​  

 

Divide each side by tan 70.

x=\frac{4.4}{\tan 70}=1.6015\approx 1.6\text{ feet}

x=  

tan70

4.4

​  

=1.6015≈1.6 feet