Answer:
The answer is b.Look below for details.
Step-by-step explanation:
Question no 1. The sequence has the common difference of 14.
t1=7
t2=21
t3=35
We have
tn=a+(n-1)d
=7+(n-1)14
=7+14n-14
=14n-7(Its not our answer)
Lets try b.
The common difference is 2 in this sequence.
t1=7
t2=9
t3=11
t4=13
We have
tn=7+(n-1)2
=7+2n-2
=2n+5(Its is our answer.) Got it.
