Answer:
solution given:
∆ABC is a right angled isosceles triangle
perpendicular [p]=base [b]=a=b
hypotenuse [h]=3ft
By using Pythagoras law
h²=p²+b²
3²=a²+a²
9=2a²
a=√(9/2)=[tex] \frac{3 \sqrt{2} }{2} [/tex]
so
a=b=[tex] \frac{3 \sqrt{2} }{2} [/tex]
