Answer:
[tex]Pr = 0.833[/tex]
Step-by-step explanation:
Given
A roll of a pair of dice
Required
The probability of getting different numbers
First, list out the sample space;
We have:
[tex]S = \{(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6),(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6),[/tex]
[tex](3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6),(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)[/tex]
[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)\}[/tex]
The total is:
[tex]Total = 36[/tex]
The outcomes of the different numbers are:
[tex]Different = \{(1, 2) (1, 3) (1, 4) (1, 5) (1, 6),(2, 1) (2, 3) (2, 4) (2, 5) (2, 6),[/tex]
[tex](3, 1) (3, 2)(3, 4) (3, 5) (3, 6),(4, 1) (4, 2) (4, 3) (4, 5) (4, 6)[/tex]
[tex](5, 1) (5, 2) (5, 3) (5, 4) (5, 6), (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) \}[/tex]
The total is:
[tex]Different = 30[/tex]
So, the probability of having a different outcome is:
[tex]Pr = \frac{Different}{Total}[/tex]
[tex]Pr = \frac{30}{36}[/tex]
[tex]Pr = 0.833[/tex]
