Answer:
Option C, The 30 m telescope can observe objects 9 times fainter, and with 3 times smaller angular size, than the 10 m telescope.
Explanation:
As we know,
The surface brightness of the object viewed through telescope is proportional to the square of the diameter of the lens
Thus, Brightness ([tex]B_{30}[/tex]) of 30 m telescope would be proportional to [tex]30^2[/tex]
Brightness of 10 m ([tex]B_{10}[/tex]} telescope would be proportional to [tex]10^2[/tex]
Thus, the ration of the two would be
[tex]\frac{B_{30}}{B_{10}} = \frac{30^2}{10^2} \\\frac{B_{30}}{B_{10}} = \frac{9}{1} \\B_{30} = 9 * B_{10}[/tex]
Thus, brightness of 30 m telescope would be able to view 9 times fainter object as compared to the 10 m telescope.
Also , 30 m telescope would be able to view 3 times smaller angular sized object as compared to the 10 m telescope
Hence, option C is correct