michealkivman
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WILL REWARD BRAINLIEST! The diameter of a circle has endpoints P(-4, -6) and Q(12, 4). Write an equation for the circle. Be sure to show and explain all work.

Respuesta :

P(-4,6) Q(12,4)

Center(Midpoint):

(-4+12/2, -6+4/2)= (4,-1)

d= (12-(-4)^2+ (4-(-6)^2(has a root over it)

d= 256+100=356(root)

Root 356= 2 radical 89
——————-=. 89
2

RADIUS IS HALF OF DIAMETER


ANSWER: (x-4) ^2+(y+1) ^2= 89





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