What is an equation of the line that passes through the point (-5,-2) and is
parallel to the line x - y = 5?

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
Parallel lines have the same slope

1) Rewrite the equation x - y = 5 into slope-intercept form and identify the slope

[tex]x - y = 5[/tex]

Subtract both sides by x

[tex]x - y -x= -x+5\\-y= -x+5[/tex]

Divide both sides by -1

[tex]y= x-5[/tex]

Now, we can tell clearly that the slope (m) of this line is 1. Therefore, a line parallel to this would also have a slope of 1.

Plugging 1 as m into [tex]y=mx+b[/tex], we get:

[tex]y=x+b[/tex]

2) Find the y-intercept (b) of the line parallel to [tex]y= x-5[/tex] and find the final equation

[tex]y=x+b[/tex]

Plug in the given point (-5,-2)

[tex]-2=-5+b[/tex]

Add 5 to both sides

[tex]-2+5=-5+b+5\\3=b[/tex]

Therefore, the y-intercept of this line is 3. Now, plugging this back into our original equation, we get:

[tex]y=x+b\\y=x+3[/tex]

I hope this helps!

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