Answer:
The pH of a 0.10 Maqueous Ba(OH)2 solution at 25°C is 13.30
Explanation:
The balanced equation is Ba(OH)2(s)→Ba2++2OH−
This indicates that the concentration is 0.2 M
We will find H+ ion concentration
As we know that
[H+][OH−]=1.0×10−14M
Given -
[OH−]=2.0×10−1M
Putting value of [OH-] in above equation we get -
[H+]=5.0×10−14M
pH=−log10[H+]
pH=−log10[5.0×10−14] = 13.30.
