How many ways can a dozen books be placed on four distinguishable shelves if no two books are the same, and the positions of the books on the shelves matter (ie. if Book 1 is to the left of Book 2, that is different from if Book 1 is to the right of Book 2)

Respuesta :

Answer:

217945728000 ways

Step-by-step explanation:

Given

[tex]Books = 12[/tex] --- 1 dozen

[tex]Shelf = 4[/tex]

The given condition implies that;

[tex]Book\ 1 = 4[/tex] ---- any of the 4 shelves

[tex]Book\ 2 = 5[/tex] --- any of the 4 shelves and either ways of book 1

[tex]Book\ 3 = 6[/tex]  --- any of the 4 shelves and either ways of book 1 and 2

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[tex]Book\ 12 = 15[/tex]

So, the number of ways is:

[tex]Ways = 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12 * 13 * 14 * 15[/tex]

[tex]Ways = 217945728000[/tex]