Answer:
[tex]x = \frac{5a-2} {7+5a}\\[/tex]
Step-by-step explanation:
Given the expressions
[tex]x = \frac{5}{9y+5}....1\\y = \frac{5}{5a-2} ...2[/tex]
Substitute 2 into 1
[tex]x = \frac{5}{9(\frac{5}{5a-2} )+5} \\x = \frac{5}{(\frac{45}{5a-2} )+5} \\x = \frac{5}{\frac{45+5(5a-2)}{5a-2} } \\x= \frac{5}{\frac{35+25a}{5a-2} }\\x = \frac{5(5a-2)} {35+25a}\\x = \frac{5(5a-2)} {5(7+5a})\\\\x = \frac{5a-2} {7+5a}\\[/tex]
