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The function f(x) is a quartic function and the zeros of f(x) are -4,-3,2 and 5. Assume the leading coefficient of f(x) is 1. Write the equation of the quartic polynomial in standard form

The function fx is a quartic function and the zeros of fx are 432 and 5 Assume the leading coefficient of fx is 1 Write the equation of the quartic polynomial i class=

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samquinnd
Answer:
f(x) = x⁴-6x³-13x²+66x+72
Step-by-step explanation:
Factors are: (x+3)(x+1)(x-4)(x-6)
[(x+3)(x+1)][(x-4)(x-6)]
[x²+3x+x+3][x²-4x-6x+24]
(x²+4x+3)(x²-10x+24)
x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72
f(x) = x⁴-6x³-13x²+66x+72

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