I need work shown as well

Answer:
Step-by-step explanation:
the area of the squared is 5 * 5 = 25
the area of the triangle is 1/2*base*height = 1/2*2*5= 5
the area of the circle is [tex]\pi[/tex][tex]r^{2}[/tex] = [tex]\pi[/tex][tex]2.5^{2}[/tex] = 19.625
now add the pieces up for the total
25+5+19.625 = 49.625 [tex]in^{2}[/tex]
:)
First, find the area of the semi-circle.
A= pi*radius squared
Find your radius. The diameter is 5, half of that is 2.5
Input into the formula
A= pi*2.5^2
=3.14*6.25
=19.625 in^2
You can round that to about 19.6 inches.
Find the area of the square
A=s^2
= 5^2
= 25 in^2
Find the area of the triangle.
A= b*h/2
= 2*5/2
= 10/2
= 5 in^2
Add it all up.
19.6+ 25 + 5= 49.6
∴ 49.6 in²
Best of luck!