The sets of ordered pairs is NOT a direct variation
- (0,0) (1,3) (2,4)
We know that the set of ordered pair are in direct variation if they lie on a straight line or we can say if the rate of change is constant.
1)
- (0,0) (-2,4) (3, -6)
From the following set of points we see that we get a straight line as:
y= -2x
Hence , the points are in direct variation.
2)
- (1, 1) (-2, -2) (3,3)
Now, these set of ordered points also satisfy the line as:
y=x
Hence, the points are in direct variation.
3)
- (10, 2) (15,3) (20,4)
Now, these set of ordered points also satisfy the line as:
y=(1/5)x
Hence, the points are in direct variation.
4)
- (0,0) (1,3) (2,4)
We find the rate of change of (0,0) and (1,3) as:
[tex]\dfrac{3-0}{1-0}=3[/tex]
The rate of change of (1,3) and (2,4) is:
[tex]\dfrac{4-3}{2-1}=1[/tex]
As the rate of change is not constant.
Hence, the points are not in direct variation.
Hence, sets of ordered pairs is NOT a direct variation is:
(0,0) , (1,3), (2,4)
Answer:
(0,0) (1,3) (2,4)
Step-by-step explanation:
Hope this helps
