Answer:
Length of the transverse axis of the given conic section = 8 units.
Step-by-step explanation:
The equation of hyperbola that has a horizontal orientation in the standard form is;
[tex]\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1[/tex] .....[1]
The center is (h, k) , the vertices are [tex](h \pm a , k)[/tex] and [tex](h , k\pm b)[/tex]
Since, the vertices are on the hyperbola, but the co-vertices are not on the hyperbola.
Since, the equation of the conic section is given as:
[tex]\frac{(x+2)^2}{16} - \frac{(y-3)^2}{9} = 1[/tex]
On comparing with equation [1]
⇒ center = ( -2 , 3 ) and
[tex]a^2 = 16[/tex]
[tex]a = \sqrt{16} = 4[/tex] units
and
[tex]b^2 = 9[/tex]
[tex]b = \sqrt{9} = 3[/tex] units
Length of the transverse axis is the distance between the two vertices, 2a = 2(4) = 8 units.
Answer:
The answer is 8
Step-by-step explanation:
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