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Find the perimeter of a rhombus having two consecutive vertices at (2, 5) and (-1, 3).
4square root of 5
4square root of 10
4square root of 13
4square root of 65

Respuesta :

Correct answer is C.

[tex](2, 5) \text{ and } (-1, 3) \\x_1=2,y_1=5,x_2=-1,y_2=3 \\ \\d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}= \sqrt{(-1-2)^2+(3-5)^2}= \sqrt{13} \\ \\P=4d \\P=4\sqrt{13} [/tex]

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