*ABCD is a rhombus with diagonals intersecting at E. If m<ABC = 4m<BAD, find m<EBC.
Well, your question is a bit incomplete that makes it worse to give you exactly what you need. But, according to the fact that diagonals intersecting, all the angles =360 degrees.
Suppose [tex]\ \textless \ BAD=x [/tex]. and [tex]\ \textless \ ABC=4x[/tex]
which means that opposite ones are equal
so, the solution is :
[tex]2(x+4x)=360[/tex]
or could be [tex]10x= 360
x=36[/tex]
So, we have : <BAD=36 and <ABC=144
And the answer is : 4m+m=180.
Do hope you will find it helpful!
