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Heater has power rating of 500W inserted in 1Kg of water for half of a minute. Water was at 20 degrees Celsius. What is the temperature of water after half a minute

Respuesta :

Answer:

23.585°C

Explanation:

500W/s = 500J/s half a minute = 30s

30 x 500J = 15000J in half a minute

the specific heat of water is 4.184J/gC

Use the specific heat formula:

(20C)(1kg)(4184J/kgC)= 83680J

83680J + 15000J = 98680J

98680J = (x)(1kg)(4184J/kgC)

98680J = 4184x

Divide

x = 23.585°C