Respuesta :

mhanifa

Answer:

  • ABCD is a kite

Properties:

  • AB = AD, CB = CD,
  • AC⊥DB, AC is angle bisector of DAB and DCB

Find x:

  • P = 140
  • 2(2x + 7 + 4x +3) = 140
  • 6x + 10 = 70
  • 6x = 60
  • x = 10

Find y:

  • 3y - 1 and 28° are complementary
  • 3y - 1 = 90° - 28°
  • 3y - 1 = 62°
  • 3y = 63°
  • y = 21°

Find z:

  • 4z and 58° are complementary
  • 4z = 90° - 58
  • 4z = 32°
  • z = 8°

Answer:

x=10

y = 21°

z=8°

Step-by-step explanation:

we have

AB = AD, CB = CD,

AC perpendicular to DB, AC is angle bisector of DAB and DCB

Perimeter = 140

2(2x + 7 + 4x +3) = 140

6x + 10 = 70

6x = 60

x = 60/6=10

x=10

again

3y - 1 +28° =90

3y - 1 = 90° - 28°

3y - 1 = 62°

3y = 63°

y = 21°

again

4z+58°=90

4z = 90° - 58

4z = 32°

z=32/4

z=8°

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