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A rigid container of O 2 has a pressure of 340 kPa at a temperature of 713 K. What is the pressure at 273°C ?

Respuesta :

maacastrobr

Answer:

260 kPa

Explanation:

To answer this problem we can use Gay-Lussac's law, which states that at a constant volume (such as is the case with a rigid container):

  • P₁T₂=P₂T₁

Where in this case:

  • P₁ = 340 kPa
  • T₂ = 273 °C ⇒ 273 + 273.16 = 546 K
  • P₂ = ?
  • T₁ = 713 K

We input the data:

  • 340 kPa * 546 K = P₂ * 713 K

And solve for P₂:

  • P₂ =  260 kPa

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