What are the roots of the equation 2x2 - 6x + 3 = 0?

Answer:
Step-by-step explanation:
The given possible roots have the form that we'd get by using the quadratic formula, so let's start with that. Here the coefficients are {2, -6, 3}, and so the discriminant (b^2 - 4ac) is (-6)^2 - 4(2)(3), or 36 - 24 = 12.
Because the discriminant is positive we know immediately that there are two different real roots.
-(-6) ± √12 6 ± √12
x = ------------------ = ---------------- These are equivalent to Answers E and F.
2(2) 4