Answer: Not a right-angled triangle
Step-by-step explanation:
Given
The sides of a triangle are [tex]7\ m, 8\ m, \text{and}\ 10\ m[/tex]
For a right-angle triangle, it must satisfy the Pythagoras theorem
[tex]a^2+b^2=c^2[/tex]
i.e. the square of the larger side must be equal to the sum of the square of the remaining two sides
Here,
[tex]\Rightarrow 7^2+8^2\ ?\ 10^2\\\Rightarrow 49+64\ ?\ 100\\\Rightarrow 113\neq 100[/tex]
Therefore, it is not a right-angle triangle
