By using trigonometric relations we will see that the area is:
[tex]A = h*tan(60\°)*/2 = tan(60\°)*h^2/2[/tex]
How to find the area of one triangular section?
Remember that the area of a right triangle is equal to the product between the cathetus divided by 2.
Sadly, here we don't have the measures of any sides of the triangle, so getting the actual area is impossible, but if we assume that some dimension is given (like the height, let's say that is h).
h is the cathetus adjacent to the 60° angle, then the other cathetus (the bottom one) is given by:
tan(60°) = x/h
x = tan(60°)*h
Then our two catheti are h and tan(60°)*h.
This means that the area will be:
[tex]A = h*tan(60\°)*/2 = tan(60\°)*h^2/2[/tex]
Here we only used trigonometric properties, so this area will work for any height given (always that the value of h is the cathetus adjacent to the 60° angle).
If you want to learn more about right triangles:
https://brainly.com/question/2217700
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