1191195 1191195
  • 29-03-2021
  • Physics
contestada

A 5.5 kg box is pushed across the lunch table. The net force applied to the box is 9.7 N. What is the acceleration of the box?

Respuesta :

astar9
astar9 astar9
  • 29-03-2021

Answer:

F=ma

a=F/m=9.7N/5.5Kg=1.8 m/s^2

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