Respuesta :

Answer:

diameter     of       the  wire   =  0.05  in  =0.05 /12   =4.167 *10 ^-3  ft

area   of cross  section    of the  wire  = A =  22/7 *  ( d /2 ) ^2  =0.786 *  (  4.167 *10 ^-3 ) ^2  =1.365 *10 ^-5  ft2  

E  =...

Explanation: