contestada

A bag contains 42 red, 45 green, 20
yellow, and 32 purple candies. You
pick one candy at random. Find the
probability that it is green or yellow.

Respuesta :

Answer:

65/139 fraction form

0.47 decimal form

Answer:

Step-by-step explanation:

Total sample space , n (s) = 139

no of green candies , n (g) = 45

no. of yellow candies , n (y) = 20

Probability that is green or yellow is

P( g or y) = P(g) + P(y)

               = n(g) / n(s) + n (y) / n(s)

               = 45 / 139 + 20 / 139

               = 65 / 139

hope it will help :)