Answer:
Numbers between 5 and 16 are:-
6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.
Therefore, total number of outcomes =11
Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-
6 , 8, 9 ,10 ,12, 14 and 15.
Number of favourable outcomes = 7
Therefore, probability of getting a number which is either a multiple of 2 or 3 is:
p(e) = \frac{7}{11}p(e)=
11
7
HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.
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