Answer:
kg•m^2/s^3
Explanation:
Here, we want to get the valid unit for power
Mathematically, power is time rate of doing work
Work is the product of force and distance
Unit for force is;
kg•ms^-2
work is;
Kg•ms^-2 • s
= kg•m^2•s^-2
Divide through by the s for time;
we have ;
kg•m^2•s^-2/s
kg•m^2•s^-3
And that is;
kg•m^2/s^3
