Answer:
v_{ average} = 5.57
Explanation:
The most probable value of a measure is
v_average = [tex]\frac{1}{N}[/tex] ∑ x_i
where N is the number of measurements
in tes case N = 3
v_{average} = ⅓ (5.63 +5.54 + 5.53)
V_{average} = 5,567
The number of significant figures must be equal to the number of figures that have the least in the readings.
v_{ average} = 5.57
