The volume occupied by 12.5 moles of nitrogen gas at STP is 280 Liters.
The given parameters;
- number of moles of the gas, n = 12.5 moles
- I mole of gas at stp = 22.4 L
The volume of occupied by the nitrogen gas at stp is calculated by comparing the given number of moles to 1 moles of at standard condition (stp), as shown below;
1 moles of gas --------------- 22.4 L
12.5 moles of gas ------------ ?
= 12.5 x 22.4
= 280 L.
Thus, the volume occupied by 12.5 moles of nitrogen gas at STP is 280 Liters.
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