Answer:
we conclude that:
[tex]\:9x^0y^{-3}=\frac{9}{y^3}[/tex]
Step-by-step explanation:
Given the expression
[tex]9x^0y^{-3}[/tex]
Apply exponent rule: [tex]a^{-b}=\frac{1}{a^b}[/tex]
[tex]\:9x^0y^{-3}=9\cdot \:\frac{1}{y^3}x^0[/tex]
Apply rule: [tex]a^0=1,\:a\ne \:0[/tex]
[tex]=9\cdot \:1\cdot \frac{1}{y^3}[/tex]
Multiply fractions: [tex]a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}[/tex]
[tex]=1\cdot \frac{1\cdot \:9}{y^3}[/tex]
Refine
[tex]=\frac{9}{y^3}[/tex]
Thus, we conclude that:
[tex]\:9x^0y^{-3}=\frac{9}{y^3}[/tex]
