Answer: 16) y=-0.5x+3 and 17) y=2x-3
Step-by-step explanation:
16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.
Since y=3 at x=0, the y-intercept is (0,3), and b=3.
Slope=[tex]\frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex] where ([tex]x_{1} ,y_{1}[/tex]) and ([tex]x_{2} ,y_{2}[/tex]) are two points on the line. Choose (0,3) and (2,2):
Slope=[tex]\frac{2-3}{2-0}[/tex]=-0.5
Plug m=-0.5 and b=3 into y=mx+b:
y=-0.5x+3
17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.
Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.
Slope=[tex]\frac{y_{2} -y_{1} }{x_{2}-x_{1} }[/tex] where ([tex]x_{1} ,y_{1}[/tex]) and ([tex]x_{2} ,y_{2}[/tex]) are two points on the line. Choose (0,-3) and (1,-1):
Slope=[tex]\frac{-3-(-1)}{0-1}[/tex]=[tex]\frac{-2}{-1}[/tex]=2
Plug m=2 and b=-3 into y=mx+b:
y=2x-3
