Respuesta :
x²+6x+8= 0
Discriminant = 6²-4·1·8 = 4
Pythagorean theorem:
x = [-6±√(6²-4·1·8)]/[2· 1] = [-6±√4]/2 = -4, -2
Zeroes: -4,-2
Discriminant = 6²-4·1·8 = 4
Pythagorean theorem:
x = [-6±√(6²-4·1·8)]/[2· 1] = [-6±√4]/2 = -4, -2
Zeroes: -4,-2