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A thin wire of length (2 m) and (1 mm2 ) cross-section area is clamped horizontally between two walls, a weight of (10 kg) is hung at the middle of the wire depressed it (2 cm). Find young's modulus?

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ajeigbeibraheem

Answer:

Young modulus  = 9.8 × 10⁹ N/m²

Explanation:

From the information given:

Stress = F/A

Stress = (10 × 9.8) / 0.001²

Stress = 9.8× 10⁷ N/m²

Strain = increase in length / initial length of wire

Strain = 0.02/ 2

Strain = 0.01

Now;

The Young modulus (Y)= stress/strain

Young modulus  = (9.8 × 10⁷ N/m²) /  0.01

Young modulus  = 9.8 × 10⁹ N/m²

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