Calculate the velocity(v) at the bottom of hill.
As we know ,
[tex] \bf\: Kinetic \: energy = \dfrac{1}{2} \times m \times {v}^{2} [/tex]
[tex] \red \bigstar \bf \: putting \: the \: values[/tex]
[tex] \rightarrow \: 25 = \dfrac{1}{2} \times 2 \times {v}^{2} [/tex]
[tex] \rightarrow \: 25 \times 2 = 1 \times 2 \times {v}^{2} [/tex]
[tex] \rightarrow \: 50 = 2 \times {v}^{2} [/tex]
[tex] \rightarrow \: {v}^{2} = \cancel \dfrac{50}{2} [/tex]
[tex] \rightarrow \: {v}^{2} = 25[/tex]
[tex] \rightarrow \: v = \sqrt{25} [/tex]
[tex] \rightarrow \: v = 5 \: m {s}^{ - 1} [/tex]
