Scenario
You have recently joined the team at A&L, an engineering firm with a broad portfolio. A&L has recently been hired to help plan a supply drop following a natural disaster. Due to conditions on the ground, the supply drop will be done from the air. Your supervisor has asked you to use that information, as well as your knowledge of kinematics, to create a supply drop plan detailing how far the payload should be from the drop site when it is delivered. Additionally, due to adverse conditions in the area, your supervisor has asked you to prepare for two contingencies.
Directions
The plane carrying the supplies will be cruising at a constant velocity of 250 miles per hour relative to the ground and at a height of 2,650 meters above the target site. Using this information, create a supply drop plan including all required information and calculations outlined below. As you are completing your supply drop plan, remember that correct SI units are a required component of your calculations and descriptions.
Construct a diagram that describes the horizontal and vertical motion of the payload. Your diagram should visually represent the initial velocity and height of the payload as it approaches the drop site. To create the diagrams, you may use drawing tools, or you may photograph or screenshot a drawing of your own. This diagram should include the following elements:
The initial velocity of the payload
The initial height of the payload
Horizontal distance to the drop site
Using your understanding of kinematic equations and the given variables in the scenario, calculate the horizontal and vertical motion of the payload to ensure it arrives at the drop site. In your calculations, account for both the horizontal and vertical motion of the payload. Your calculations should address the following:
Initial velocity of the payload when launched
The velocity of the payload when it hits the ground
Following your calculations, describe the equations used in calculating the vertical and horizontal motion of an object. In your descriptions, address the following:
What is the relationship between vertical and horizontal motion in kinematics equations?
How did you analyze the vertical motion of the payload in your solution?
How did you analyze the horizontal motion of the payload in your solution?
What other kinematics principles did you consider in analyzing the motion of the payload?

Respuesta :

Answer:

 t = 23.255 s,   x = 2298.98 m,    v_y = - 227.90 m / s

Explanation:

After reading your extensive writing, we are going to solve the approach.

The initial speed of the plane is 250 miles / h and it is at an altitude of 2650 m; In general, planes fly horizontally for launch, therefore this is the initial horizontal speed.

As there is a mixture of units in different systems we are going to reduce everything to the SI system.

         v₀ₓ = 250 miles h (1609.34 m / 1 mile) (1 h / 3600 s) = 111.76 m / s

         y₀ = 2650 m

Let's set a reference system with the x-axis parallel to the ground, the y-axis is vertical. As time is a scalar it is the same for vertical and horizontal movement

Y axis  

       y = y₀ + v₀ t - ½ g t²

the initial vertical velocity when the cargo is dropped is zero and when it reaches the floor the height is zero

       0 = y₀ + 0 - ½ g t²

       t = [tex]\sqrt{ \frac{2 y_o}{g} }[/tex]

       t = √(2 2650/ 9.8)

       t = 23.255 s

Therefore, for the cargo to reach the desired point, it must be launched from a distance of

       x = v₀ₓ t

       x = 111.76 23.255

       x = 2298.98 m

at the point and arrival the speed is

        vₓ = v₀ₓ = 111.76

     

vertical speed is

         v_y = v_{oy} - gt

          v_y = 0 - gt

          v_y = - 9.8 23.25 555

         v_y = - 227.90 m / s

the negative sign indicates that the speed is down

in the attachment we have a diagram of the movement

Ver imagen moya1316