Answer:
The sampling distribution of X, for a sample of size 16, will be approximately normal with mean 2 mm and standard deviation 0.01 mm.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For the population:
Mean 2 mm, standard deviation 0.04 mm
Describe the sampling distribution of X (for a sample of size 16).
Sample of size 16 means that [tex]n = 16[/tex]
By the Central Limit Theorem, approximately normal with mean 2 and standard deviation [tex]s = \frac{0.04}{\sqrt{16}} = 0.01[/tex]