Answer:
Choice A, C and E
Step-by-step explanation:
Your table is poorly presented
Given
x y
[tex]\begin{array}{cc} {3} & {1.47} \ \\ {5} & {2.45} \ \\ {9} & {4.41} \ \ \end{array}[/tex]
First, we calculate the constant of proportionality (k)
[tex]k = \frac{y}{x}[/tex]
For (3,1.47)
[tex]k = \frac{1.47}{3}[/tex]
[tex]k = 0.49[/tex]
For (5,2.45)
[tex]k = \frac{2.45}{5}[/tex]
[tex]k = 0.49[/tex]
For (9,4.41)
[tex]k = \frac{4.41}{9}[/tex]
[tex]k = 0.49[/tex]
From the above calculations, the constant of proportionality is 0.49.
So, the usable rows must also have 0.49 as their constant of proportionality
Choice A
[tex](x,y) = (2,0.98)[/tex]
[tex]k = \frac{0.98}{2}[/tex]
[tex]k = 0.49[/tex] --- This is usable
Choice B
[tex](x,y) = (7,4.45)[/tex]
[tex]k = \frac{4.45}{7}[/tex]
[tex]k = 0.64[/tex] --- This is not usable
Choice C
[tex](x,y) = (6,2.94)[/tex]
[tex]k = \frac{2.94}{6}[/tex]
[tex]k = 0.49[/tex] --- This is usable
Choice D
[tex](x,y) = (1,0.54)[/tex]
[tex]k = \frac{0.54}{1}[/tex]
[tex]k = 0.54[/tex] ---- This is not usable
Choice E
[tex](x,y) = (8,3.92)[/tex]
[tex]k = \frac{3.92}{8}[/tex]
[tex]k = 0.49[/tex] --- This is usable
Answer:
A, C, and E
Step-by-step explanation:
khan said it was correct
trust me
