Answer:
[tex]Solution,\\Midpoint of coordinates (a ,b) and (c,d) is given by:\\(x,y) = (\frac{a+b}{2} , \frac{c+d}{2}) \\Therefore, coordinate of B is\\(\frac{-9-1}{2},\frac{-4+6}{2}) = (\frac{-8}{2},\frac{2}{2}) = (-4 , 1)[/tex]
[tex]Similarly,\\E(4, -3) = (\frac{-4+x}{2},\frac{1+y}{2}) where, (x,y) are the coordinates of D\\or, 4=\frac{x-4}{2} and -3 = \frac{y+1}{2}\\or, 8 = x - 4 and -6 = y+1\\or, x= 12 and y = -5\\Therefore, the coordinates of D are (12,-5)[/tex]
