Answer:
[tex]F=3.6\times 10^6\ N[/tex]
Explanation:
Given that,
The mass of International Space Station, m = 419,455 kg
It orbits around the Earth at an altitude of, h = 400,000 m
The radius of Earth, [tex]r=6.37\times 10^6\ m[/tex]
The mass of the Earth, [tex]m_e=5.97 \times 10^{24}\ kg[/tex]
We need to find the approximate gravitational force on the Station due to Earth's gravity. The formula for the gravitational force between the satellite and the Earth is given by :
[tex]F=G\dfrac{mm_e}{(r+h)^2}\\\\F=6.67\times 10^{-11}\times \dfrac{419455\times 5.97 \times 10^{24}}{(6.37 \times 10^6+400000 )^2}\\\\F=3.6\times 10^6\ N[/tex]
So, the required force on the station due to Earth's gravity is [tex]3.6\times 10^6\ N[/tex].
