Respuesta :

i believe the answer is 2m/s

Answer:

The bird is flying at a velocity of [tex]v=2\frac{m}{s}[/tex]

Explanation:

You should use the equation for the kinetic energy, that is:

[tex]K_{E}=\frac{1}{2}mv^{2}[/tex]

where [tex]K_{E}[/tex] is the kinetic energy, m is the mass of the bird and v is its velocity.

Solving for v:

[tex]mv^{2}=2K_{E}[/tex]

[tex]v^{2}=\frac{2K_{E}}{m}[/tex]

[tex]v=\sqrt{\frac{2K_{E}}{m}}[/tex]

And replacing the values given in the problem you have:

[tex]v=\sqrt{\frac{2*8J}{4kg}}[/tex]

[tex]v=\sqrt{\frac{16J}{4kg}}[/tex]

[tex]v=\sqrt{4\frac{m^{2}}{s^{2}}}[/tex]

[tex]v=2\frac{m}{s}[/tex]