The earth rotates through one complete revolution every 1,440 minutes. Since the axis of rotation is perpendicular to the equator, you can think of a person standing on the equator as standing on the edge of a disc that is rotating through one complete revolution every 1440 minutes. Find the angular velocity of a person standing on the equator.

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Answer:

The angular velocity of a person standing on the equator is approximately [tex]7.272\times 10^{-5}[/tex] radians per second.

Explanation:

The Earth rotates at constant speed. From Rotational Physics, the angular velocity ([tex]\omega[/tex]), measured in radians per second, is defined by the following formula:

[tex]\omega = \frac{2\pi}{T}[/tex] (1)

Where [tex]T[/tex] is the period of rotation of the Earth, measured in seconds.

If we know that [tex]T = 86400\,s[/tex], then the angular velocity of a person standing on the equator is:

[tex]\omega = \frac{2\pi}{86400\,s}[/tex]

[tex]\omega \approx 7.272\times 10^{-5}\,\frac{rad}{s}[/tex]

The angular velocity of a person standing on the equator is approximately [tex]7.272\times 10^{-5}[/tex] radians per second.