Respuesta :
Answer:
n = 1 10¹⁰ electron
Explanation:
For this exercise we will use Coulomb's law
F = k q₁ q₂ / r²
where it indicates that the value of the force is 7.61 10⁻²¹ N, the distance between the objects is r = 1.94 10⁻³ m and the charge on the objects has the same charge q₁ = q₂ = q,
F = k q² / r²
q = [tex]\sqrt{ \frac{ k \ q^2}{k} }[/tex]
let's calculate
q = [tex]\sqrt{ \frac{ 7.61 \ 10^{-21} \ (1.93 \ 10^{-3})^2 }{9 \ 10^{9} } }[/tex]
q = √(3.182 10⁻¹⁸)
q = 1.783 10⁻⁹ C
the charge of an electron is q₀ = 1.6 10⁻¹⁹ C, therefore
q = n q₀
n = q / q₀
n = 1,78 10⁻⁹ / 1.6 10⁻¹⁰
n = 1.06 10¹⁰ electron
the number of electrons must be integer
n = 1 10¹⁰ electron
