Answer:
5.2 ft
Step-by-step explanation:
[tex] \cos 30 \degree = \frac{6}{length \: of \: platform} \\ \\ \frac{ \sqrt{3} }{2} = \frac{6}{length \: of \: platform} \\ \\ length \: of \: platform = \frac{2 \times 6}{ \sqrt{3} } \\ \\ length \: of \: platform = \frac{12\sqrt{3} }{ 3} \\ \\ length \: of \: platform =4 \sqrt{3} \\ \\ length \: of \: platform =4 \times 1.732 \\ \\ length \: of \: platform = 5.228 \\ \\ length \: of \: platform = 5.2 \: ft[/tex]
