18 What is the equation of the line that is perpendicular to y = -x – 10 and contains point (-12, 1)? A y = X - 8 B y = - 15 C y = -x - 8 D y = 3*+ 17​

Respuesta :

Answer:

The equation of the line that is perpendicular to y = -x – 10 and contains point (-12, 1)

[tex]y=x+13[/tex]

Please note there is something wrong with the  values given question. This is correct answer.

Step-by-step explanation:

Slope of line y = -x – 10 is m1=-1

Since slope of perpendicular lines are negative reciprocal of each other

Slope of other line is m2=1

Equation of line contains point (-12, 1) and having slope m2=1 is

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-1 = 1(x+12)[/tex]

[tex]y =x+12+1 \\y = x + 13[/tex]