Answer:
m(∠CAG) = 35°
Step-by-step explanation:
From the figure attached,
Apply Pythagoras theorem in ΔCAG,
Length of AC = [tex]\sqrt{(27)^2+(36)^2}[/tex]
= [tex]\sqrt{729+1296}[/tex]
= [tex]\sqrt{2025}[/tex]
= 45
Now find the tangent of the given angle CAG,
tan(∠CAG) = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]
= [tex]\frac{CG}{AC}[/tex]
m(∠CAG) = [tex]\text{tan}^{-1}(\frac{31.5}{45} )[/tex]
= [tex]\text{tan}^{-1}(0.7)[/tex]
= 34.992°
≈ 35°
