Answer:
Option C: Na2C2O4 + Pb(NO3)_2 = PbC2O4 + 2NaNO3
Explanation:
Na2C2O4 + Pb(NO3)_2
For it to be a double placement reaction, the cations and a ions will switch places in the product.
Now, on this reaction side;
Cations are; Na+ and Pb+
Anions are; C2O4^(-) and (NO3)^(-)
The product side will yield;
Na2C2O4 + Pb(NO3)_2 = 2NaNO3 + PbC2O4
